Gujarati
Hindi
14.Waves and Sound
medium

A string is stretched so that its length is increased by $\frac{1}{\eta }$ of its original length. The ratio of fundamental frequency of transverse vibration to that of fundamental frequency of longitudinal vibration will be

A

$\eta :1$

B

$1:\eta $

C

$\sqrt \eta  :1$

D

$1:\sqrt \eta  $

Solution

$\frac{{{{\rm{f}}_T}}}{{{{\rm{f}}_\ell }}} = \sqrt {\frac{{\frac{{\rm{T}}}{\mu }}}{{\frac{{\rm{r}}}{{\rm{s}}}}}}  = \sqrt {\frac{{\frac{{\rm{T}}}{{\rho {\rm{A}}}}}}{{\frac{{{\rm{T}}\ell }}{{\rho {\rm{A}}\Delta \ell }}}}}  = \sqrt {\frac{{\Delta \ell }}{\ell }}  = \frac{1}{{\sqrt \eta  }}$

Standard 11
Physics

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